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Trigonometry
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State the domain of f(x)=log_3(x+1)- (x^2-4)^1/2
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Let's analyse both terms. \(\log_3(x+1)\) has a domain simply where \(x + 1 > 0\), or \(x > -1\). Similarly, \((x^2-4)^{1/2}\) has a domain where \(x^2 - 4 \ge 0\) or \((-\infty, -2] \cup [2, \infty)\). The above two conditions have to be simultaneously fulfilled.
\[State the Domain for f(x)=\log_3{x+1} -\sqrt{x^2-4}\]
Ok, Thank You very much! :)
No problem! What do you get for the answer?
\[(-\infty, -2] U [2,\infty) \]
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Since they both have to meet the requirement, then would that be correct?
Remember that \(x > -1\) also, from the log term.
Both requirements meaning: First: \(x \in (-1, +\infty)\) Second: \(x \in (-\infty,-2] \cup [2, \infty)\) Take the "intersection" of both.
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