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Mathematics 17 Online
OpenStudy (danielbarriosr1):

Someone please help me graphing

OpenStudy (danielbarriosr1):

\[x^2-10=-10\]

OpenStudy (danielbarriosr1):

@mathmale

OpenStudy (danielbarriosr1):

How do I graph that?

OpenStudy (anonymous):

|dw:1395938447551:dw|

OpenStudy (anonymous):

You could simplify this equation. You could add 10 on both sides to get rid of -10, and your equation will be \[x^2=0\] From here, you could simplify even further and it will x=0. That means your line will be located at (0,0) and it will be vertical.

OpenStudy (mathmale):

I would simplify x^2-10=-10 first. Add 10 to both sides. What do you get by doing that?

OpenStudy (danielbarriosr1):

So x^2=0

OpenStudy (mathmale):

@sujuexob2st : Could you justify your statement, please? "From here, you could simplify even further and it will x=0. That means your line will be located at (0,0) and it will be vertical." The equation x^2 = 0 has two solutions. What are they? Are they lines? points? curves?

OpenStudy (danielbarriosr1):

I do not know

OpenStudy (mathmale):

I posted a response perhaps 15 min. ago, but OpenStudy was down. If f(x)=x^2=0, there are two solutions: 0 and 0. Evaluating f(x) at each of these produces two y values: 0 and 0. thus, the final result consists of two points, (0,0) and (0,0). they are one and the same point. so just graph (0,0) and you're done. Again, sorry for the delay!! lo siento.

OpenStudy (danielbarriosr1):

Just a point and that's it?

OpenStudy (danielbarriosr1):

thanks a lot

OpenStudy (mathmale):

That's right. If y ou'd like to move on to a new problem, I'd be happy to help. How fast that happens depends, of course, on how fast OpenStudy is at the moment.

OpenStudy (danielbarriosr1):

Im ok thanks

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