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-21√27x^9
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the x^9 is also in the radicand
\[-21\sqrt{27x ^{9}}\]
Go to mathway.com
i know but it doesn't show the steps
First, you need to separate the terms \[-21\times \sqrt{27}\times \sqrt{x ^{9}}\] The √27 simplifies into √9*√3, which is 3√3. The √x^9 is the same as x^(9/2), which becomes \[x^4\sqrt{x}\] So if you put it all together, you have \[-21\times3\sqrt{3}\times x^4\sqrt{x}\] \[-21\times3\times x^4 \times \sqrt{3 \times x}\] And your final answer is \[-63x^4\sqrt{3x}\]
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Ah! Thanks so much! :DD
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