Convert the given function into a logarithmic function. Please help, I give medals!
F(x) = 3.64e^(0.06x)
We can start by taking the natural log of both sides of the equation.
What is the natural log
The natural logarithm is defined as a logarithim who base is e = 2.718. . .
Okay, so what would we do?
We can let F(x) = y. When we take the natural log of both sides, we have\[\ln (y) = \ln(3.64*e ^{0.06x} )\]
Okay, now what?
Applying logarithim rules, we can split the right hand side of this equation into two natural logs. \[\ln(y) = \ln(3.64) + \ln(e^{0.06x})\]
How do you find the inverse?
We are finding the inverse of the original equation
Okay, so what do we do after In (y) = In(3.64) + In (e^0.06x)
Since ln(x) and e^x are inverses of each other, the right hand side of the equation reduces as follows\[\ln(y) = \ln(3.64) + 0.06x\]
Okay, do I have to reduce In (3.64)
Depends if the answers are in decimal approximations or not. In the end, we solve for x and find that\[x = (50/3)( \ln(y) - \ln(3.64) )\]
Where did 50/3 come from?
from the 0.06. 0.06 = (6/100) = (3 / 50). When we multiply across the equal sign, then we have 50/3.
So what is the logarithm?
What is a logarithm? In general?
The inverse of an exponential function
Right
I need help writing the logarithm
Writing it? The solution for this exercise will be what we established above, where \[x = (50/3)(\ln(y)-\ln(3.64))\] We can further reduces this using log rules and we can write\[x = (50/3) \log(\frac{ y }{ 3.64 })\]
So is that the final answer?
Yes. But where I wrote log, I meant to put ln
Okay so (50/3) In (y/3.64) ?
Yes, x = (50/3)ln(y/3.64)
Okay, thank you :)
Your Welcome. Its really important to know the exponential and logarithm rules for these kind of things. Good luck.
I just have another quick question, what will the graph of this logarithm look like
It looks like this http://www.wolframalpha.com/input/?i=50%2F3+log%28y%2F3.64%29
Okay, thanks :)
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