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find the area of the region bounded by the equations by integrating ( i ) with respect to x and (ii) with respect to y x=36-y^2 x=y-6
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1/ find intersect points 2/ take integral
To find the points do I start with \[6-\sqrt{x}=x+6\]?
let them equal, solve for y, you will have y = 6 and y = -7 replace back to get corresponding x = 0 and x = -13 now you have 2 points, draw the pic
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How did you end up with y=6 and y=-7?
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