Convert (-5,pi/4) to rectangle coordinates. a. (5sqrt2/2,5sqrt2/2) b. (sqrt2/2,sqrt2/2) c. (5sqrt3/2,5/2) d. (-5sqrt2/2,-5sqrt2/2)
\[Polar coordinates are \in (r,\theta)\] \[x = r*\cos \theta\] \[y = r * \sin \theta\]
The coordinates will be written as usual: (X,Y)
\[x=-5\cos \pi/4 \]\[y=-5\sin \pi/4\]
Yep. Do you know both the cosine and sine of pi/4? They're the same.
\[\sqrt{2}/2\]
There ya go. You got this problem by the balls.
lol so b is the answer?
can you help me with one more question?
or try to
No, silly! You forgot to multiply by -5 for both x and y.
x = -5*sqrt(2)/2 y = -5*sqrt(2)/2
oh crap. ok
I can try to help.
Find the product of the complex numbers. Express your answer in trigonometric form. z1 = 7(cos(15) + isin(15)) z2 = 2(cos(110) + isin(110)) z1 = 14(cos(125) + isin(125)) z1 = 9(cos(125) + isin(125)) z1 = 5(cos(-95) + isin(-95)) z1 = 14(cos(265) + isin(265))
Ooooo, not help with this. Not an irrational number guy.
Sorry.
lol its ok. thank you though!!!
Unreal number guy I mean lol
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