Question

Quadratic Equations
6x=4-18x^2
MEDAL REWARDED!!

Answer 1

@texaschic101 ?

Answer 2

I know what the quadratic equation is :D

Answer 3

I am just confused with this, that's all.

Answer 4

@whpalmer4 ?

Answer 5

the answer I got was 3

Answer 6

go here http://www.geteasysolution.com/6x=4-18x%5E2

Answer 7

This is Quadratic Equation @Chris911, thanks anyways :D

Answer 8

@MarziaJacksonCute, can you tell me how you got 3?

Answer 9

I know the first thing we're supposed to do is to make it (ax^2+bx=c) & equal to 0

Answer 10

Add '3' to each side of the equation.
-3 + 3 + x2 = 0 + 3

Combine like terms: -3 + 3 = 0
0 + x2 = 0 + 3
x2 = 0 + 3

Combine like terms: 0 + 3 = 3
x2 = 3

Simplifying
x2 = 3
( that's how my teacher told me)

Answer 11

Hmm.... I don't think this is Quadratic Equations?
We are supposed to use \[x=-b +/- \sqrt{b^2 - 4ac} / 2a\]

Answer 12

@MarziaJacksonCute ?

Answer 13

I know but that's what my teacher told me

Answer 14

Okay..............

Answer 15

@mathslover ?

Answer 16

Thx for the medal :D

Answer 17

Well first try to bring all the terms on a same side :

\(\mathsf{6x = 4 - 18x^2 }\\
\textbf{Transpose -18x^2 and 4 to the Left Hand Side} \\
\sf{6x - 4 + 18x^2 = 0 \\
18x^2 +6x - 4 = 0 }\)

Answer 18

Okay

Answer 19

Now compare the above equation ( \(\sf{18x^2 + 6x - 4 =0 }\)) with the basic quadratic equation ( \(\sf{ax^2 + bx + c = 0}\) )and find the values of a , b and c. Can you do this?

Answer 20

Thanks @mathslover I can do it from there, :D

Answer 21

Can you help me with other similar problems?

Answer 22

I know how to solve, just confused how to rearrange it that's all :D

Answer 23

You're welcome! Good Luck and let me know what you get so that I can verify it.

Also, I will try to help but as I told earlier that today is my exam so I may leave any time.

Just tag me in your question, I will be there!

Answer 24

Hmmm.......
x^2=8x?

Answer 25

Okay @mathslover, I wish you good luck on your exam! :D

Answer 26

you can think of \[x^2 = 8x\] as \[x^2 - 8x + 0 = 0\] so what two numbers multiplied together are 0 but add to -8. Only two numbers are -8 and 0 so you write \[(x-8)(x+0) = 0\] hence x = 8 and 0

Answer 27

And how about 4x^2=9?

Answer 28

There are two methods to do this :

i) Transpose 8x to Left Hand side :
\(\sf{x^2 - 8x = 0}\)

And now compare this with \(ax^2 + bx + c = 0\) as you can see, c = 0 (there is no constant term) and b is "-8" and a is "1"

Just plug-in these values in the quadratic equation and solve :

\(\color{blue}{\sf{\cfrac{-b \pm \sqrt{b^2-4ac}}{2a}}}\)

ii) Divide both sides by "x"

\(\color{orange}{\sf{\cfrac{x^2}{x}} }= \color{red}{\sf{\cfrac{-8x}{x}}}\)

Cancel the possible terms and find x.

Answer 29

Thx both of you! :D
I wish I can give 2 medals though

Answer 30

* it is 8x not "-8x" (in the second way)

Answer 31

Okay

Answer 32

Take my medal back and give it to Tyler @31356 - I have enough medals for now. Tyler explained well and I will be more happy if Tyler is awarded with a medal.

Answer 33

Okay, lol :D

Answer 34

There we go :D

Answer 35

And how about 4x^2=9?

Answer 36

I should go now. Bye! And Good Luck.

Also, good work @Tyler1992 - Keep it up.

Answer 37

And how about 4x^2=9?

Answer 38

Take square root both sides. And solve for x.

Or transpose 9 to LHS

4x^2 - 9 = 0

Solve it by finding the values of a, b and c and then put it in quadratic equation.

Tyler will explain you how to solve it! I have to go. Bye for now.

Answer 39

Okay thanks :D

Answer 40

\[4x^2 = 9\] can be written as \[4x^2 + 0x - 9 = 0\] and then best to use quadratic formula i think.

Answer 41

or i can show you another way to factor that if you want

Answer 42

Oh it's fine :D
Thanks though

Answer 43

Thanks for your help :D
I figured out the others :D

Answer 44

No problem! :)

Answer 45

Wait........

Answer 46

How about 3x^2-10=12-31x?

Answer 47

Now that one is a bit awkward?

Answer 48

Its looks tricky but its actually not so bad :) so first you want to move everything on the right side to the left\[3x^2 - 10 -12 - 31x = 0\] now just combine like terms\[3x^2 - 31x - 22 = 0\] then use quadratic

Answer 49

Okay, thanks! :D

Answer 50

and i made a mistake

Answer 51

Where?

Answer 52

+31x

Answer 53

Oh okay, thanks for the correction :D

Answer 54

No more problems left :D

Answer 55

Thanks! :D

Answer 56

You're welcome!

Answer 57

I can't stop saying "Thanks" lol :D

Answer 58

Got to go, bye :D

Answer 59

See ya :)