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A ketone have an absorption peak centred around 1710cm^-1 . From this info deduce a value for the force constant,k, of the C=O double bond.
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\(E_n=hc\bar\nu=\hbar \sqrt{\dfrac{k}{μ}}(n + 1 )\) \(\mu\)= is the reduced mass
Dont really understand
I have 2 equations One with c which is speed of light One without
find the energy first (with the wavenumber) then find k, the spring constant
how do i calculate energy?
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i got the reduced mass is 6.857
Wavelength = frequency x planck constant?
Energy not wavelength
From wavenumber convert to wavelength. Using wavelength x frequency = c then use frequency x planck's constant got me the value 3.399x10^-20
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