HELP WILL FAN AND GOLD VERY HARD three times a first number minus a second number equals negative forty. The first number plus twice the second number equals negative four a.Define variables and formulate a system of linear equations from this situation. b.What are the numbers
3n-m=-40 n+2m = -4 does this look right so far?
hmm, i'm pretty sure
3 times a number (3n) minus a second number(m) = -40
can you solve for n on the second equation i gave you and tell me what it equals?
n=-2?
n+2m = -4 can you walk me through how you got n=-2?
HONESTLY I'M SO CONFUSED LOL can you you walk me through how to get n?
get n alone! n+2m = -4 subtract 2m from both sides!
so... n =?
n=-4-2m
ok! good. now that we know this, lets go back to our first equation 3n-m = -40. can you guess what we do from here or do you need a clue?
we plug in n?
wooohoo!
so 3(-4-2m)=-40m ??
we have 3(n)- m = -40 put everything that n = inside those parentheses. 3(-4-2m) - m = -40
and we distribute the 3?
we do, and then we solve for m. once we have m we plug that in to one of the two equations we came up with and find n and we are finished!
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