HELP WILL FAN AND GOLD VERY HARD
three times a first number minus a second number equals negative forty. The first number plus twice the second number equals negative four
a.Define variables and formulate a system of linear equations from this situation.
b.What are the numbers
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OpenStudy (anonymous):
3n-m=-40
n+2m = -4
does this look right so far?
OpenStudy (anonymous):
hmm, i'm pretty sure
OpenStudy (anonymous):
3 times a number (3n) minus a second number(m) = -40
OpenStudy (anonymous):
can you solve for n on the second equation i gave you and tell me what it equals?
OpenStudy (anonymous):
n=-2?
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OpenStudy (anonymous):
n+2m = -4
can you walk me through how you got n=-2?
OpenStudy (anonymous):
HONESTLY I'M SO CONFUSED LOL can you you walk me through how to get n?
OpenStudy (anonymous):
get n alone!
n+2m = -4
subtract 2m from both sides!
OpenStudy (anonymous):
so... n =?
OpenStudy (anonymous):
n=-4-2m
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OpenStudy (anonymous):
ok! good. now that we know this, lets go back to our first equation
3n-m = -40. can you guess what we do from here or do you need a clue?
OpenStudy (anonymous):
we plug in n?
OpenStudy (anonymous):
wooohoo!
OpenStudy (anonymous):
so 3(-4-2m)=-40m ??
OpenStudy (anonymous):
we have 3(n)- m = -40
put everything that n = inside those parentheses.
3(-4-2m) - m = -40
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OpenStudy (anonymous):
and we distribute the 3?
OpenStudy (anonymous):
we do, and then we solve for m. once we have m we plug that in to one of the two equations we came up with and find n and we are finished!