Standard form? Is this right? 37. slope = ; (2, 8) y-8=3/4(x-2) y-8=3/4x-6/4 y=3/4x+26/4 4y=3x+26 -3x+4y=26
hey have you tried gegebra
sorry geogebra
It can do standard form? I've used it for graphing but this isn't about graphing.
it can help with slope. Let me look at your problem and see if I can see if you are right. ahh gotcha you are wanting to see if you wrote it down right
Yeah I wasn't sure if I made it into standard form correctly given slope and one point.
it looks right but not positive
Ok well then I guess I'll keep waiting to see if someone can tell me if it is or not. It's just for a study guide but it is worth a small part of my grade and I'd really like to do good on it.
I don't see what they gave you for the slope. But if the slope is ¾ , it looks ok, but often standard form means: variables in alphabetical order and leading coefficient on the first variable is POSITIVE. To be safe, I would write -3x+4y=26 as 3x - 4y = - 26
Oh right! It's been a long time since I've done these and yes slope was 3/4!
If I do a few more could you tell me if they're right?
yes
slope = -2/5 ; (3, -9) y+9=-2/5(x-3) y+9=-2/5x+6/5 This is where I get stuck. Do I multiply the whole thing by 5 or do I subtract 9 on both sides first?
You can take either step. But standard form does not use fractions, and at some point we will have to multiply by 5 to "clear the denominator" In fact, I would make that the very first step for this problem. \[ y+9 = -\frac{2}{5}(x-3) \\ 5y +45 = -2(x-3)\] but if we pick up with \[ y+9=-\frac{2}{5}x+\frac{6}{5} \] I would multiply by 5 to get \[ 5y +45= -2x + 6\]
So my answer would be 2x+5y=-39
yes
Awesome thank you I think I got it now!
notice for do I subtract 9 on both sides first? \[ y+9=-\frac{2}{5}x+\frac{6}{5} \\ y = -\frac{2}{5}x+\frac{6}{5} -9 \] again we could multiply by 5. or we can add 2/5 x to both sides to get \[ \frac{2}{5}x + y = \frac{6}{5}-9 \] we could simplify 6/5 - 9 to -39/5. or we could multiply by 5 (on both sides) \[ 2x + 5y = 6-45 \\ 2x + 5y = -39 \]
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