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Mathematics 9 Online
OpenStudy (anonymous):

Click for the question

OpenStudy (anonymous):

Find x when y =10

OpenStudy (anonymous):

OpenStudy (anonymous):

@ParthKohli

OpenStudy (anonymous):

Hi, are you aware of the Pythagoras Theorem?

OpenStudy (anonymous):

yes very much

OpenStudy (anonymous):

i did the problem half way through

OpenStudy (anonymous):

and i am stuck on a equation

OpenStudy (anonymous):

OK, let's see how we can work with it here.

OpenStudy (anonymous):

What equations did you get?

OpenStudy (anonymous):

give me a minute i will tell u what i did

OpenStudy (anonymous):

OpenStudy (anonymous):

@ParthKohli @ParthKohli2

OpenStudy (anonymous):

\[10^2 = (x-3)^2 + CD^2 \Rightarrow 100 = x^2 - 6x + 9 + CD^2\]\[\Rightarrow CD = \sqrt{100 - x^2 + 6x - 9}\]So\[AC = x + \sqrt{100 - x^2 + 6x - 9}\]\[(x + \sqrt{100 - x^2 + 6x - 9})^2 = (x+4)^2 + (x - 3)^2\]

OpenStudy (anonymous):

Oh wait... you've already replied. Didn't see that, sorry.

OpenStudy (anonymous):

you can try solving that on WolframAlpha.

ganeshie8 (ganeshie8):

we're not given ABC is a right triangle ?

OpenStudy (anonymous):

it is actually

ganeshie8 (ganeshie8):

who said ? and where is the complete question lol ?

OpenStudy (anonymous):

^

OpenStudy (anonymous):

oh, we should take the other right triangle.

OpenStudy (anonymous):

Find x when y =10

ganeshie8 (ganeshie8):

where it was mentioned that ABC is a right triangle ?

ganeshie8 (ganeshie8):

if it is about diagram :- There was no square box at angle B. So we cannot assume it as right triangle.

OpenStudy (anonymous):

OpenStudy (anonymous):

Now it is

OpenStudy (anonymous):

lol, but not according to the question.

OpenStudy (anonymous):

It is misprinted it is lighter in the picture so it is not visible

ganeshie8 (ganeshie8):

ohk, then its easy just plugin each value and see which one works

OpenStudy (anonymous):

The answer is 11 but i don't know how so should plug in the options and see which one works

OpenStudy (anonymous):

got it @mathbrz

OpenStudy (anonymous):

lol

ganeshie8 (ganeshie8):

the x value must satisfy both right triangles : 1) ABC 2) the right triangle wid one side as "y"

OpenStudy (anonymous):

The answer is 11 but i don't know how so should plug in the options and see which one works

OpenStudy (anonymous):

ok

ganeshie8 (ganeshie8):

b|dw:1395987482001:dw|

OpenStudy (anonymous):

\[(x + \sqrt{100-(x-3)^2})^2 = (x-3)^2 + (x+4)^2\]

OpenStudy (anonymous):

solve for x

OpenStudy (anonymous):

|dw:1395987509742:dw|

ganeshie8 (ganeshie8):

plugin x = 11, and see if it satisfies both right triangles, it does satisfy, so 11 is the answer. ^^thats how u check options :)

OpenStudy (anonymous):

that's the smarter way lol @ganeshie8

ganeshie8 (ganeshie8):

|dw:1395987565405:dw|

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