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Mathematics 18 Online
OpenStudy (anonymous):

2^x=10?

OpenStudy (anonymous):

the answer is 2^333 repeating b/c it gives u 10.056107. and u basically get 10.

OpenStudy (anonymous):

sorry i didnt explain it so well im not so good at that.

OpenStudy (anonymous):

haha. its fine. I just need to know how to do it with log form

OpenStudy (anonymous):

its for my test tomorrow and no calculator

OpenStudy (nincompoop):

?

OpenStudy (anonymous):

i need to put 2^x=10 in log form, so log2^10=x

OpenStudy (anonymous):

no calculator?!!!!!! oh wow im sorry. i take trig and we get graphing calcu;ators

OpenStudy (anonymous):

but how would I solve from there?

Parth (parthkohli):

Another way is just to convert from exponential to logarithmic.\[a^b = c \Rightarrow \log_a c = b\]

OpenStudy (nincompoop):

you still have to solve for x

OpenStudy (anonymous):

thats what i did. but I need to find x

OpenStudy (nincompoop):

log rules :)

Parth (parthkohli):

Just did.

OpenStudy (anonymous):

and I don't know how to do that without a calculator

OpenStudy (nincompoop):

10 = 5+2

OpenStudy (nincompoop):

does that ring a bell?

OpenStudy (anonymous):

l.o.l.

Parth (parthkohli):

@nincompoop 10 = 5 + 2 = 7? Hao? Pls explan. OP pls.

OpenStudy (nincompoop):

log (10) = log(2) + log (5)

Parth (parthkohli):

k

OpenStudy (nincompoop):

ni hao ma?

Parth (parthkohli):

I'm good, thanks. @ktmart1n3 got it?

OpenStudy (nincompoop):

log rules :P

OpenStudy (anonymous):

lol. sorta

Parth (parthkohli):

Yeah, log rules!

OpenStudy (anonymous):

so, my test to solve the equation. and it says 2^x=10 x=? what goes in the question mark space?

OpenStudy (anonymous):

lol. is it going to be log(2)+log(5)?

OpenStudy (nincompoop):

no

OpenStudy (nincompoop):

\[\log_ax=\frac{ \log_bx }{ \log_ba }\]

OpenStudy (nincompoop):

change base formula http://www.purplemath.com/modules/logrules5.htm

Parth (parthkohli):

The above gives a pretty useful result, that is,\[\dfrac{1}{\log_x a}=\log_a x\]

OpenStudy (anonymous):

so, if i want to answer this question for what x is, im going to need my calculator?

Parth (parthkohli):

Do you need the answer in log form?

OpenStudy (nincompoop):

most likely in log form, an approximation would require calculator

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

What is this shenanigans

Parth (parthkohli):

If so, just use the following:\[a^b = c \Rightarrow \log_a c = b\]

OpenStudy (anonymous):

alright, thank u guys.

Parth (parthkohli):

Just make 'em right substitutions, and you're done with it.

OpenStudy (nincompoop):

again 10 = 5+2 :P

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