Question

Assuming sufficient differentiability , show that \(div(u\times v)=v.\text{ curl } u-u.\text{ curl } v\)

Answer 1

any help ?

Answer 2

This is easy as hell :O

Answer 3

@BSwan @ikram002p .. try doing it..

Answer 4

i can help with this :P

Answer 5

no .. wait let @BSwan do it.. she is an idiot.. she doesn't do anything!

Answer 6

naa ill do it :P

Answer 7

check this out

Answer 8

ok fine!

Answer 9

ok idk .. :-|

Answer 10

oh come on try.. start by taking the divergence of the cross product!

Answer 11

ok let me see
div (u × v)= grad . (u× v )
so tripple product !

Answer 12

yea.. correct!