Question

intergrate cos^2 (3x) dx

Answer 1

rewrite it as \[\frac{1}{2}\cos(6x)+1\]

Answer 2

Thanks, i appreciate it.

Answer 3

yw

Answer 4

wow i made a typo sorry

Answer 5

forgot parentheses, it should be
\[\frac{1}{2}\left(\cos(6x)+1\right)\]

Answer 6

using the identity
\[\cos^2(x)=\frac{1}{2}\left(\cos(2x)+1\right)\] only with \(3x\) instead of \(x\)

Answer 7

you do sine the same way

Answer 8

don't worry i understood what you meant

Answer 9

k good