More doubts:
1.A body with Volume V neither sinks nor floats in a liquid. The vessel containing it falls with an acceleration g/2. Then the volume of solid inside liquid in falling condition is ....
The answer is V itself. I do not know how that is same.
Whatever the acceleration of the vessel, if weight is balanced by upthrust at rest, it will always be so. (this is how I understand the wording of your question)
Then what about the pseudo force acting?
The pseudo force act equally on the body and on the sustaining water. Since upthrust is equal to "weight" of displaced water, it varies also accordingly.
*acts
okay thanks :) 2.Three rods of identical cross sectional area and made from same metal form the sides of an isoceles right angled triangle. ABC rt angled at B. The temperature at points A and B are T and (root2)T in steady state. temperature at C is Tc Find Tc/T
Here I considered this as a resistance circuit question. Current through AB=Current through BC. But I am not getting the answer in options.
Tc/T = 2\(\sqrt 2-1\) ?
Yeah that;s what I got. The answer given is \[\dfrac{\sqrt{3}}{\sqrt{2}+1}\]
The solution is explained as Heat flowing in BC=Heat flowing in CA
But for me it looks as they are parallel and hence same current cannot flow.
Is the triangle open at point B?
No figure is given.
Could it be a wrong solution?
ok
Typo in your answer? I find \(\dfrac{3}{\sqrt{2}+1}\)
Nope that was answer given. I can see that if we equate according to their solution there is no chance of getting root(3).
But how can they equate those currents?
The thing is Ta and Tb are impose by an external source. So you cannot equate heat flows in AB and BC, only in Bc and CA.
Sorry I dont get it. The diag in my mind is this: |dw:1396013264346:dw|
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