Question

Consider the following cross:
Parent 1: YyTt
Parent 2: YyTt
Using the rules of probability, determine the probability that the offspring will show YyTT genotype?

1/8
1/16
1/2

Answer 1

the space between the numbers is supposed to show them as fractions

Answer 2

Just draw a Punnett square.
Any idea how that works?

Answer 3

its been like four years since ive even seen the punnett square...so, no i dont. lol

Answer 4

You take the male alleles and put them on the top row
And put the female alleles in the left column of the square.

You take 1 letter of each trait. We have 2 traits here: Y and T

So for YyTt, we have 4 different allele combinations : YT, Yt, yT and yt
They're both the same so it doesn't matter which one you put on top and which on the left.

Now you draw the square.
For example I'll show a punnett square with the cross breed of AaBb x AaBb
You take the 2 parent alleles and combine them. So Ab x AB becomes AABb because we have 2 capital A's, 1 capital B and 1 lowercase b


Now do the same for your combination