Question

Help with a couple questions please

1. The temperature of 100 g of liquid water in a calorimeter changes from 25°C to 50°C. How much heat was transferred? The specific heat of liquid water is 4.18 J/g-°C.

10.5 J

10.5 kJ

100 J

100 kJ

2. A 200 g block of a substance requires 520 J of heat to raise its temperature from 25°C to 45°C. Solve.

0.46

0.90

0.13

0.39

Answer 1

Number two I got 0.13...

Answer 2

use \(q=m*C*\Delta T\)

Answer 3

So q= mass(100g) * C(4.18 J/g-C) * T(50-25=25C) This is for question one?

Answer 4

yes

Answer 5

I get when multiplying across 10,450... Then do I convert?

Answer 6

the answer is 10.5 right? Is it kj or j? kj right?

Answer 7

yes kJ

Answer 8

Thank you very much!!