Question

Which relation is a function?


A.
(6, 5), (1, 1), (6, 4)


B.
(0, 1), (2, 3), (2, 5)


C.


(8, –2), (–2, 5), (6, 0)


D.


(–2, 3), (–5, 9), (–5, 3)

Answer 1

medal*

Answer 2

the one that doesn't have X REPEATS

Answer 3

what do you mean?

Answer 4

notice, you have an ordered pair set
say for example the first set

(6, 5), (1, 1), (6, 4)
x y x y x y

Answer 5

how would i know if its x of y?

Answer 6

"x" is always the 1st in the pair, and "y", well is the 2nd

Answer 7

so d os outa the answer?

Answer 8

http://www.mathsisfun.com/definitions/ordered-pair.html

Answer 9

so the set that doesn't have a 1st number, or "x" value, repeated

let us check the first set for example \(\bf ({\color{red}{ 6}}, 5), (1, 1), ({\color{red}{ 6}}, 4)\) do you see any "x" repeats?

Answer 10

the 6 and the other 6?

Answer 11

yeap, thus is not a function then

Answer 12

wut about 1,1?

Answer 13

(1 , 1)
x y

x = 1 y =1

Answer 14

oh

Answer 15

answer=B?

Answer 16

let's see B set \(\bf (0, 1), ({\color{red}{ 2}}, 3), ({\color{red}{ 2}}, 5)\) so.. what do you think?

Answer 17

grrr

Answer 18

if you pluck out, from the set
all 1st value
and all 2nd values

the set that has no REPEATED 1ST VALUE is a function

Answer 19

its c because the -2 the first time is y and the second is x

Answer 20

right?

Answer 21

C has two -2
but you're correct, they're not both "x" values
the 1st one is a "y" value or 2nd value

and the 2nd -2 is a "x" value

and yes, (8, –2), (–2, 5), (6, 0) has x = 8 x = -2 and x = 6

8, -2, 6 no repeats, thus is a function

Answer 22

yay!

Answer 23

thank you

Answer 24

\(\huge \unicode{x270c}\)

Answer 25

yw