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OpenStudy (vshiroky):
OpenStudy (vshiroky):
72?
OpenStudy (vshiroky):
@agent0smith
OpenStudy (vshiroky):
@jdoe0001
OpenStudy (vshiroky):
Is my 72 right?
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OpenStudy (jdoe0001):
ohh ahemm \(\bf \begin{array}{cccllll}
\textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\
\textit{something }&={\color{red}{ \textit{some value }}}&\textit{something else}\\ \quad \\
y&={\color{red}{ n}}&x&\implies y={\color{red}{ n}}x
\end{array}\\ \quad \\
x=60\qquad y=24\qquad 60={\color{red}{ n}}(24)\)
solve for "n" to find the "constant of variation"
is not 72 though
OpenStudy (vshiroky):
ummmmm
OpenStudy (jdoe0001):
hmm lemme recheck that... maybe I got my units mixed up =(
OpenStudy (jdoe0001):
... nope, I think they're ok
OpenStudy (vshiroky):
I still don't understand. That's not the equation I was given and when I did mine I got 72
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OpenStudy (vshiroky):
is it 144?
OpenStudy (jdoe0001):
nope... I'm afraid 72 makes sense to me
since 3 * 60 is 180 thus 3 * 24 will be 72
making the constant of variation = 3
I'm thinking I may have the output as the input up there
OpenStudy (vshiroky):
So it is 72 then
OpenStudy (jdoe0001):
it makes logical sense.... trying to see ... what's off in the procedure
OpenStudy (vshiroky):
Thank you.
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OpenStudy (jdoe0001):
anyhow... , I was using "x" as the given in the function, thus
but the function above is correct