y /((x-(-6)) = x^8 + (-7) Use implicit differentiation to find the slope of the tangent line to the curve at point (1, -6/37)
Do you know how implicit differentiation works? Also, is the following your equation (just for clarity): \[\frac{y}{x + 6} = x^8 - 7\]
how did you do that??
If you press the equation button below a reply you can use formatting. It doesn't work when posting a question; for that reason, if you're posting a complicated equation (probably not necessary in this case) I find it's best to post it in the comments.
ah ok thanks
In reference to the question, it would be good to know this: What do you know about implicit differentiation at this point? Do you know how to start the problem using it?
yes well I know that if I diff. \[x ^{8}+7 \] I will get \[8x ^{7}\]
It seems like you're not actually especially used to implicit differentiation. Essentially, implicit differentiation is differentiating an entire equation with respect to a variable, in this case x. To get started, I suggest you multiply throughout by x+6 and simplify the right hand side; this should make the calculus essentially trivial.
\[(x ^{8}-7)(x+6)\]
Yup. Expand that out, then differentiate the equation (including the left side) with respect to x.
\[y'=8x^{7}\]
?
Uhm, you seem to have dropped a couple of terms completely! \[(x^8 - 7)(x + 6) = x^9 + 6x^8 - 7x - 42\]
oh you factored
that would be \[9^{8}+48x ^{7}-7\]
\[9x ^{8}\]
Yup.
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