Question

find the volume of the solid obtained by rotating the region bounded by the given curves. y=(25-x^2)^(1/2), y=0, x=2, x=4 rotate about x-axis

Answer 1

I have x=-5,5 and I found the volume to be 500pi/3 ...is this correct?

Answer 2

You found x=-5, 5, but I believe they gave you boundaries at x=2 and x=4. x=-5, 5 are outside of those, right?

Answer 3

aha you are right, silly of me XD

Answer 4

ok so, then what I have

Answer 5

pi int 2->4 (25-x^2) dx after simplifying

Answer 6

That looks good to me now. :)
Other than that small mix-up at the beginning, I think you have the process down!

Answer 7

cool let me get the final result, hmm

Answer 8

pi(100-(64/3)-(50-(8/3))

Answer 9

94pi/3

Answer 10

that looks good to me as well. :D

Answer 11

sweetness, thanks!!

Answer 12

glad to help!