find the volume of the solid obtained by rotating the region bounded by the given curves. y=(25-x^2)^(1/2), y=0, x=2, x=4 rotate about x-axis

Question

anonymous · Answer

I have x=-5,5 and I found the volume to be 500pi/3 ...is this correct?

accessdenied · Answer

You found x=-5, 5,  but I believe they gave you boundaries at x=2 and x=4.  x=-5, 5   are outside of those, right?

anonymous · Answer

aha you are right, silly of me XD

anonymous · Answer

ok so, then what I have

anonymous · Answer

pi int 2->4 (25-x^2) dx after simplifying

accessdenied · Answer

That looks good to me now.  :)
Other than that small mix-up at the beginning, I think you have the process down!

anonymous · Answer

cool let me get the final result, hmm

anonymous · Answer

pi(100-(64/3)-(50-(8/3))

anonymous · Answer

94pi/3

accessdenied · Answer

that looks good to me as well.  :D

anonymous · Answer

sweetness, thanks!!

accessdenied · Answer

glad to help!