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Mathematics 8 Online
OpenStudy (anonymous):

The capacities (in L) of two oil-storage tanks are x and y. The tanks are initially full; 1400L is removed from them by taking 40% of the contents of the first tank and 10% of the contents of the second tank. (a) Express y as a function of x, (b) Find f(500). I can do the math; I just need a little help setting up the equation(s)

OpenStudy (anonymous):

Let's first let the capacity of the first tank be x and the capacity of the second tank be y.

OpenStudy (anonymous):

Knowing this, we know that 1400L is equal to 40% of x and 10% of y, correct?

OpenStudy (anonymous):

How would we express this as an equation?

OpenStudy (anonymous):

1400L = .4x + .1y ?

OpenStudy (anonymous):

Correct. If we want to express y as a function of x, then just isolate y.

OpenStudy (anonymous):

14000L = 4x + y y=14000L - 4x (?)

OpenStudy (anonymous):

I multiplied by 10 to remove the decimals then isolated y. We still get the same answer in the end, yes?

OpenStudy (anonymous):

Yes, that equation is correct. Do you know how to find f(500)?

OpenStudy (anonymous):

not sure where in the equation it would be.

OpenStudy (phi):

(a) Express y as a function of x means do what you just did: y=14000L - 4x you can rename "y" to f(x), and write it as f(x) = 14000L - 4x

OpenStudy (anonymous):

f(500) means that you're letting x = 500.

OpenStudy (anonymous):

In other words, what you have to do is plug in 500 into the equation you got.

OpenStudy (anonymous):

so f(x) =14000L - 4(500) f(x) =14000L - 2000

OpenStudy (anonymous):

Correct. f(500) = 12000L

OpenStudy (phi):

yes, but the L stands for liters. the 2000 is also in liters

OpenStudy (anonymous):

okay. wasn't sure if I should continue to simplify since the variable was not explicit

OpenStudy (anonymous):

L isn't a variable, it's just the unit, and x was in the same units :)

OpenStudy (anonymous):

sigh. I overthink things and make a simple question harder than it is. Thankee-sai to you both.

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