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Mathematics 22 Online
OpenStudy (love10129151):

can some one explain how to work them out please

OpenStudy (love10129151):

25.\[\frac{ 4\sqrt{150} }{ ? \sqrt{189x}}\]

OpenStudy (jdoe0001):

\(\bf \color{blue}{189\implies 3\cdot 3\cdot 3\cdot 7\implies 3^2\cdot 3\cdot 7 \\ \quad \\ 150\implies 2\cdot 3\cdot 5\cdot 5\implies 2\cdot 3\cdot 5^2}\\ \quad \\ \quad \\ \cfrac{ 4\sqrt{150} }{ \sqrt{189x}}\implies \cfrac{4\sqrt{{\color{blue}{ 2\cdot 3\cdot 5^2}}}}{\sqrt{{\color{blue}{ 3^2\cdot 3\cdot 7}}}\cdot x}\)

OpenStudy (love10129151):

ok @jdoe0001 can you explain one more

OpenStudy (jdoe0001):

ok

OpenStudy (love10129151):

\[\frac{ 4\sqrt{6} }{ \sqrt{30} }\]

OpenStudy (love10129151):

@jdoe0001

OpenStudy (love10129151):

27. \[(2\sqrt{5}+3\sqrt{7})^{2}\]

OpenStudy (jdoe0001):

you'd do the same, you factor the radicands and see what you can take out and cancel like terms

OpenStudy (jdoe0001):

\(\bf \cfrac{ 4\sqrt{6} }{ \sqrt{30} }\implies \cfrac{ 4\sqrt{2\cdot 3} }{ \sqrt{2\cdot 3\cdot 5} }\implies \cfrac{ 4\cancel{\sqrt{2\cdot 3}} }{ \cancel{\sqrt{2\cdot 3}}\cdot \sqrt{5} }\)

OpenStudy (jdoe0001):

\(\bf (2\sqrt{5}+3\sqrt{7})^2\implies (2\sqrt{5})^2+(3\sqrt{7})^2\implies 2^2\sqrt{5^2}+3^2\sqrt{7^2}\)

OpenStudy (love10129151):

@deshawn1

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