Solve for x
2^(2x-4) x 8^(x-2) = 1/16^(x-2)

Question

Solve for x
2^(2x-4) x 8^(x-2) = 1/16^(x-2)

anonymous · Answer

$$(2^{2x-4}) x (8^{x-2}) = 1/16^{x-2}$$

anonymous · Answer

the x between the brackets is suppose to be a multiply sign

anonymous · Answer

$$2^{\left( 2x-4 \right)}\times 8^{\left( x-2 \right)}=\frac{ 1 }{ 16^{(x-2)} }=\left(16 \right)^{-\left( x-2   \right)}$$

anonymous · Answer

write 
$$8=2^3 and~ 16=2^4$$

anonymous · Answer

so you need to make all the bases the same number like when adding and subtracting exponents?

anonymous · Answer

$$8^{x-2}=\left( 2^3 \right)^{(x-2)}=2^{3\left( x-2 \right)}=2^{\left( 3x-6 \right)}$$

anonymous · Answer

similarly for 16 ,then you can simplify.

anonymous · Answer

ohhh okay, I think I get it. Thank  you!

anonymous · Answer

yw

anonymous · Answer

This was my resulting answer 
5x-10 log2 2    = -4x + 8 log2 2
5x – 10            = -4x + 8
5x + 4x            = 8 +10
9x                    = 18
x                      = 18/9
x                      = 2
I was wondering if it was correct