Question

Need help with 3 questions please I need to finish this by today will give medal+fan (:
(attached pictures)

Answer 1

any ideas on the GCF?

Answer 2

no not really i dont really understand any of this :/ ):

Answer 3

do you know what GCF means?

Answer 4

yes greatest common factor

Answer 5

hmm well... what does that mean though?

Answer 6

http://static.prometheanplanet.com/images/resources/resource-thumbnails/thumb-nalg1-7-1-15-diagram-thumb-lg-png.png <-- so you'd find it like in that example

Answer 7

im confused though isnt part a and b the same thing?

Answer 8

A wants the GCF of all 4 terms B is to factor it out expression

when you factor out, you do use the GCF of the terms, yes

Answer 9

same pretty much
in A you'd factor the expression and in B the same, in B it'd give 2 equal factors

Answer 10

same, in A B and C you'd factor the expression, in A and B it gives two factors, in C three

Answer 11

sooo all im pretty much doing for all three questions is factoring them?

Answer 12

yeap

Answer 13

thanks, im not good with too many words

Answer 14

yw

Answer 15

x-intercepts would be like 0 = -16x^2+24x+16
factor and solve :)

Answer 16

soo i just factor it? if only the questions would just say things more simpler :P

Answer 17

lol yes factor it

for example, x^2 + 5x+6 =0
becomes (x+2)(x+3)=0
so x = -3 and -2 in this example :)

Answer 18

Okay thank you! what about Part B?

Answer 19

if the coefficient attached to the x^2 is negative then it has a max
if it is positive then it has a min

Answer 20

oh okay well that makes sense but how do i find the coordinates of the vertex?

Answer 21

http://www.mathexpression.com/vertex-of-a-quadratic-equation.html

x = -b/2a

so for your problem a = -16 and b = 24
plug in and find x
once you get x, plug in into original equation and solve for y

Answer 22

for this you can factor by grouping

for Example:
IF x^3+3x^2-x-3 then you can factor out a x^2 from the first two terms
x^2(x+3) - x - 3 then you can factor a negative from the last two
x^2(x+3) - (x+3) then you can factor out a (x+3)
so (x+3)(x^2-1) and if you want, x^2-1 = (x+1)(x-1)
so you get (x+3)(x+1)(x-1)

it would be the same idea/steps for your problem :)

Answer 23

okay thank you (: and could you tell me what it means what are the "zeroes"

Answer 24

for example
the zeros of (x+3)(x+1)(x-1)
are x = -3, -1, and 1

Answer 25

i can see how'd you get the -1 and 1 but what about the -3?

Answer 26

(x+3)(x+1)(x-1)=0
becomes (x+3)=0 (x+1)=0 (x-1)=0 solve for x for each :)

that's how I got it

Answer 27

Ahh okay thank you (: for all of this

Answer 28

you're welcome ^_^

Answer 29

well i better get to work thanks again for explaining (: