Question

cos(pi-o)+ sin(pi/2 +0)=0 verifying the identity

Answer 1

http://frank.harvard.edu/~jason/APCalc/Image57.gif <--- expand the functions using the sum identities

Answer 2

cos Pi = -1 ; and sin Pi/2 = 1, then
cos (Pi -0) + sin (Pi/2 + 0) = 0

Answer 3

cos(pi-o)+ sin(pi/2 +0)=0
LS= cos(pi-o)+ sin(pi/2 +0)
LS=cos(pi)+sin(pi/2)
LS=0+0
therefore 0=0, LS=RS

Answer 4

because...: