sketch the curve with the given polar equation by first sketching the graph of r as a function of theta in Cartesion coordinates. r=1-cos(theta)

Question

mathmale · Answer

Hope you're willing and able to use the Draw utility.
Draw cos theta on the interval [0,2Pi].
Next, draw -cos theta on that same interval.
Next, shift the whole graph upward by 1 unit (due to the +1 in r=1-cos theta).

mony01 · Answer

would that be the answer?

mathmale · Answer

No. I am following the directions in this problem; what I've asked you to do is what you're supposed to do.  Now the idea is you need to translate this first graph into a polar plot.

mathmale · Answer

Let theta = 0, pi/6, pi/4, pi/3, pi/2, and so on, and from your first graph obtain the corresponding lengths of r.

mony01 · Answer

can you show me?

mathmale · Answer

I'd be glad to do that, but first I'd like to see some of YOUR work?  I need to know from where you are coming in understanding this material.  earlier I asked you to sketch the graph of y=cos theta, on [0,2Pi], but you haven't done that yet.