what is the sum of all the even numbers between 88 and 0 including 88 and 0

Question

anonymous · Answer

Okay, so $$
a_n  = 0+2+4+\ldots +88
$$Let $$
b_n = \frac 12 a_n = 0+1+2+\ldots +44
$$
Well $$
\sum a_n = \sum 2\times b_n = 2\sum b_n
$$
Such is one way to look at it.

anonymous · Answer

Likely they want you to use arithmetic  sum formula... it is something like $$
S_n = n\left(\frac{a_1+a_n}{2}\right)
$$

anonymous · Answer

For this formula, $n$ is the number of terms $45$, $a_1$ is the first term $0$ and $a_n$ is the last term $88$.

anonymous · Answer

So $$
S_{45}  = 45\left(\frac{0+88}{2}\right)
$$

anonymous · Answer

So that means that the integer sum of all even numbers between 88 and 0 including those is 44 * 45 which is 1980.

anonymous · Answer

http://www.wolframalpha.com/input/?i=sum+0+to+44+of+2n Yeah, that is consistent with wolfram.