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A polynomial function with zeros 5,5i, and -5i
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If a, b, c are zeros of a polynomial, then the polynomial will be: k * (x-a) * (x-b) * (x-c) where k is a constant and can be just 1.
So how will I write the polynomial function in standard form with those zeros 5,5i,-5i
First multiply (x - 5i) * (x + 5i). (use the fact that (a+b)(a-b) = a^2 - b^2) Then multiply the above result by (x - 5).
So is the answer x^3-5x^2+25x-125
yes!
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Any time you have roots -bi and bi you will have factor (x+bi)(x-bi) and that product always equals a sum of squares x^2 + b^2. In this case x^2 + 25. you don't have to FOIL.
So you only have to FOIL (x - 5)(x^2 + 25)
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