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Mathematics 21 Online
OpenStudy (anonymous):

For the function y = f(x), what is the ordered pair for the point on the graph when x = p + 1? (x, f(p)) (x, p + 1) (p + 1, f(p + 1)) (p + 1, f(p))

OpenStudy (anonymous):

In terms of x & f(x), what coordinates would any point have?

OpenStudy (anonymous):

I have no clue what that means :/

OpenStudy (anonymous):

If you put x into a function (such as f(x)) where will you plot the point associated with that value of x?

OpenStudy (anonymous):

I don't know

OpenStudy (anonymous):

A function is typically defined as a relationship between two values, the first usually called x and the second called either y or f(x). For every value of x you put into the function you are expected to get one value for y(or f(x)), this then can be plotted on a graph as the ordered pair (x,y)

OpenStudy (anonymous):

Im sorry I just don't get it

OpenStudy (anonymous):

As a bit of advise, the definition of a function is an important one to understand in algebra onward. Sometime I would suggest finding a better definition than my own, from a teacher, textbook or anyone else. f here is a function of x, f(x). It depends on the value of x to determine what it's value is. Here we have an alternative value for x, p + 1. If x = p + 1, what does f(x) equal?

OpenStudy (anonymous):

I'm sorry nevermind you don't have to help

OpenStudy (anonymous):

I can still help you figure out the answer. I won't give you the answer though.

OpenStudy (anonymous):

I know I don't just want the answer but im just not understanding

OpenStudy (anonymous):

Well, with what I was just asking, x is equal to p+1, so that means any place you see x, you can replace it with that instead.

OpenStudy (anonymous):

Okay but what is P

OpenStudy (anonymous):

From what I can tell it's just p

OpenStudy (anonymous):

Well crap

OpenStudy (anonymous):

(p + 1, f(p + 1)) y means that F has a letter x inside the parenthesis, f(x) we know x is the same as p+1 instead of having an X lets use p+1 (p+1,_____) Now for y...since we know p+1 means x, lets put x with f f(p+1) Now we have (p + 1, f(p + 1))

OpenStudy (anonymous):

Oops I meant to say Now for y...since we know p+1 means x, lets put p+1 with f

OpenStudy (anonymous):

-sigh- I hate math haha okay I think I get it

OpenStudy (anonymous):

instead of using x just use p+1...that also includes inside f(__)

OpenStudy (anonymous):

C!

OpenStudy (anonymous):

Yup

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