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I need help with this calculus problem...
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\[A=\int^7_02\pi ydx\]
then is just be 2piyx, from 0 to 7
That gives me 343pi/2
343pi/2 doesn't come close to the answer options
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Oh we forgot to add the base area
How would I do that?
\[Area = \int\limits_{a}^{b} 2\pi f(x) \sqrt{1 + (dy/dx)^2} dx\]
just find f'(x) and plug it in the formula, then evaluate
Thank you so much!
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answer is D
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