A travel agency books holiday tours to Italy, Greece, and other countries in Europe. A supervisor notes that the probability that a client visits Greece on a tour is 0.28, and the probability that a tour includes Italy is 0.55. The probability that a client visits both Greece and Italy on the same tour is 0.11.
What is the probability that a client chooses Greece, or Italy, or both countries, on a tour?

Question

A travel agency books holiday tours to Italy, Greece, and other countries in Europe. A supervisor notes that the probability that a client visits Greece on a tour is 0.28, and the probability that a tour includes Italy is 0.55. The probability that a client visits both Greece and Italy on the same tour is 0.11. 
What is the probability that a client chooses Greece, or Italy, or both countries, on a tour?

anonymous · Answer

@ariyanna @Battlehero6 @CloverRacer @dragonfly22 @Destinymasha @EducateMe @esshotwired @Jack1 @mony01 @ParthKohli

anonymous · Answer

Vip list?

anonymous · Answer

@EducateMe knew to this site and just needed help ASAP .

anonymous · Answer

.94

anonymous · Answer

@EducateMe that's not a choice though .

whpalmer4 · Answer

Is 0.61?

anonymous · Answer

@whpalmer4 thats not a choice either ..

whpalmer4 · Answer

Is there any particular reason you don't want to share the list?

anonymous · Answer

by .55 I'm thinking it's 55% am I right or wrong?

mony01 · Answer

0.72

anonymous · Answer

@mony01 whats the formula you used to figure that out ? @whpalmer4 what list ?

whpalmer4 · Answer

the list of answer choices

mony01 · Answer

is 0.72 in the list?

anonymous · Answer

A)
0.27
B)
0.36
C)
0.72
D)
0.83

anonymous · Answer

@mony01 yes it is , but I thought it would be .83 can you explain how you got your answer ?

whpalmer4 · Answer

added the probabilities of getting Italy and of getting Greece and subtracted the probability of getting both (otherwise you double-count)

I inadvertently subtracted 0.11 twice, which is why I inquired about 0.61.

mony01 · Answer

i added 0.28 and 0.55 which equals 0.83. Then i subtract 0.11, which gave me 0.72.

anonymous · Answer

@mony01 you were right . Thank you . Can you look at this one to ? I think it is .67 or 67% . 
In Hillcrest School, 36% of middle school students are in Grade 6, 31% are in grade 7, and 33% are in grade 8.
	
If a middle school student is selected randomly, what is the probability that the student is either in grade 6 or in grade 7?

mony01 · Answer

i think you might be right 67%

whpalmer4 · Answer

Yes, 67% is right.  If we take a total of 100 students, 36%*100 = 36 are in grade 6, 31%*100=31 are in grade 7, and 33%*100 = 33 are in grade 8.  36+31 are in grade 6 or 7, so we would have a probability of randomly selecting one of them of $$P = \frac{36+31}{100} = 0.67 = 67\%$$