Question

find a area of a segment of the circle cut off by a chord that has an arc of 90 degrees. the radius of the circle is 12

Answer 1

i have the answer I don't understand how my teacher got it its 36 * pie - 72

Answer 2

is that the whole problem?

Answer 3

I have no idea where - 72 came from I got 36 * pie easily

Answer 4

also you will need 90/360 = x/ area of the circle

Answer 5

or 1/4 is equal to x/ 144 * pie which equals 36 * pie

Answer 6

well the formula for the area of segment is
( (theta*pi / 360 )- sin (theta/2) . cos (theta/2) ) r^2
=> (90 pi/360 - sin(45 degree). cos(45 degree) ) r^2
=> (pi/4 - 1/2) (144)

solve it further and you would get the answer..
hope it helped

Answer 7

im only in geometry we are not allowed equations we have not learned yet )=

Answer 8

and I don't understand too

Answer 9

alright then
find the area of sector with a 90 degree angle in the first step and then subtract the area of the triangle

Answer 10

triangle????

Answer 11

triangle?

Answer 12

well can you guys see the triangle now..??

Answer 13

yes

Answer 14

@bryantj is it clear ??

Answer 15

oh yeah now I get it 1/2 b*h = 72 so 36*pie-72

Answer 16

Alright then...:D
I hope that now you could solve such questions easily...cos i guess that now the approach is clear to you :D

Answer 17

yes ty