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Chemistry 21 Online
OpenStudy (highschoolmom2010):

Round off each of these measurements to three significant figures. a.98.473 L b.0.000 763 21 cg c.57.048 m d. 12.17°C e. 0.007 498 3 * 10^4 mm f. 1764.9 mL

OpenStudy (gebooors):

A) 98.5 L B) 0.000 763 cg, nulls at the beginning are not significant C) 57.1 m D) 12.2 C E) 0.00750 * 10^4 mm, last null is significant in the end of decimal number F) convert first to litres, try then yourself

OpenStudy (highschoolmom2010):

1.7649 liters 1.76

OpenStudy (gebooors):

Fine! You got it!

OpenStudy (highschoolmom2010):

i still dont understand b and e....

OpenStudy (gebooors):

These can be expressed in another way: 0.00076321 cg = 0.000 0076321 g Null in front of other numbers in decimal number are not negative, So this could be 0.000 00763 g

OpenStudy (gebooors):

E) could be 74.983 mm = 75.0 mm Does this help?

OpenStudy (highschoolmom2010):

wouldnt i like have to make it scientific notation?

OpenStudy (gebooors):

D) is 7.63*10^-6 g

OpenStudy (highschoolmom2010):

for b so i wouldnt have to put it into scientific notation....?

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