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Mathematics 8 Online
OpenStudy (anonymous):

g

OpenStudy (accessdenied):

Could you explain your set up (while I work on what I am thinking about and we will be able to compare) ?

OpenStudy (anonymous):

yes: I'm only looking at a quarter of the centered at origin circle.

OpenStudy (anonymous):

(the upper quarter right one)

OpenStudy (anonymous):

I'm using the shell method. So, circumference of shell is 2pi(R-x)

OpenStudy (anonymous):

height= sqroot(1-x^2)

OpenStudy (anonymous):

width=dx

OpenStudy (anonymous):

do the integral

OpenStudy (anonymous):

from 0 to 1

OpenStudy (anonymous):

multiply by 4 to get total volume

OpenStudy (accessdenied):

I don't think you can split it into four parts and use only one quadrant. The piece on the second quadrant is actually larger because it is further away than the one on the interior, right? |dw:1396115457763:dw| Instead, try splitting it into the top half and the bottom half. You can still integrate from -1 to 1 and R+x or R-x.

OpenStudy (accessdenied):

Then you just take the top half integral and multiply by 2.

OpenStudy (anonymous):

OHHHHHHHHHH i didnt see this.

OpenStudy (anonymous):

Sudden revelation!

OpenStudy (anonymous):

I will try it. I'll be back in a couple of seconds.

OpenStudy (accessdenied):

Yep, that seems correct to me. :)

OpenStudy (anonymous):

oh that sense of satisfaction :)

OpenStudy (accessdenied):

Yea, that threw me for a loop as well because I was thinking "well of course these four quadrants are the same size, it has to work?" and then I drew the picture and thought about how it worked out there. :p

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