Question

the plane through the points p1(-2,1,4) , p2(1,0,3) that is perpendicular to the plane 4x-y+3z=2

Answer 1

two planes are perpendicular <=> normals to planes are perpendicular

Answer 2

also, normal to a plane is perpendicular to every line that lies within the plane

Answer 3

so you could cross p1p2 with the normal of given plane,
that gives normal to the plane u want

Answer 4

normal to the required plane = \(\overrightarrow{p_1p_2} \times \left< 4, -1, 3\right >\)

Answer 5

thanks .. :)

Answer 6

once u have normal,
use one of the given points to plug in a(x-x1) + b(y-y1) + c(z-z1) = 0

Answer 7

^thats one way

Answer 8

another way is to simply setup two equations in a, b, c
and solve them

Answer 9

pick whichever stone u like

Answer 10

okay