Let u = <-5, -9>, v = <6, 8>. Find -8u - 2v.
Just apply the math to the vector. Multiply vector u by -8, multiply vector v by 2. Find the difference.
and to multiply the vector by a scalar (such as -8 or 2), just multiply each component of the vector by the scalar. For example, u = <1,4> 3u = 3*<1,4> = <3*1,3*4> = <3,12>
u=<40, 72> ?
Yeah, when you apply the scalar factor to vector u, you will get that. Do the same for vector v.
v=<-12,-16> ?
Err, try again. Your y-component seems to be off.
Woops, -18?
Err where are you getting the negative from for the y component? 2<6, 8> =
oh I thought the 2 was negative.. so it's just 12 and 16?
You can look at it as -2, but we won't deal with that for now. Right, so we simplified the problem to... <40, 72> - <12, 16> = ??
When adding or subtracting vectors, you only add and subtract within the same component, if you get what I'm saying lol.
<28, 56> ?
Dingdingding, if this was a rack of ribs, it would be filling my tummy. Good job.
haha thank you!!
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