A solution of salt and water contains 70 grams of water per 140 milliliters of the solution. If 1 mole of water weighs 16 grams, _____ moles of water would be present in 35 milliliters of the solution. [Round off your answer to two decimal places]

Question

A  solution of salt and water contains 70 grams of water per 140 milliliters of the solution. If 1 mole of water weighs 16 grams, _____ moles of water would be present in 35 milliliters of the solution. [Round off your answer to two decimal places]

ganeshie8 · Answer

$\large  \frac{70~grams}{140~millileters}$

ganeshie8 · Answer

$\large  \frac{70~grams}{140~millileters} \times \frac{1~mole}{16~grams}$

anonymous · Answer

N1V1=N2V2     
N1= no. of moles before
V1= volume before
V2=volume after
N2=no. of moles after
now you can solve!!

anonymous · Answer

2. something

ranga · Answer

140ml of solution has 70 grams of water
35ml of solution will have how many grams of water?

divide that by 16 grams to find the number of moles of water.

ganeshie8 · Answer

$\large  \frac{70~grams}{140~millileters} \times \frac{1~mole}{16~grams} \times  35 ~millileters$

ganeshie8 · Answer

cancel watever u can, including units also

anonymous · Answer

2.1moles

ranga · Answer

check your calculations.  should be 1.something

ranga · Answer

I have a question about one of the numbers in this problem: Shouldn't 1 mole of water weigh 18 grams instead of 16 grams as stated in the problem?  
Molecular weight of H20 = 2H + O = 2*1 + 16 = 18.
Therefore, 1 mole of water weighs 18 grams.

ganeshie8 · Answer

ahh yes it should be 18g/mol^^

ganeshie8 · Answer

mistake in the question