Question

When 1.470 × 10^3 J of heat energy is added to 36.9 g of hexane, C6H14, the temperature increases by 17.6 °C. Calculate the molar heat capacity of C6H14.

Answer 1

Calculated molar mass of hexane, then amount of substance n.
Molar heat capacity is n/ (energy * change of temperature),
Unit is mol / J * degrees of C

Answer 2

hm the formula above is incorrect, moles should be at the bottom because the units are \(energy/K*mol\).

you wanna use: \(q=n*C*\Delta T\) and isolate C, specific heat capacity.

you can substitute \(n=\dfrac{m}{M}\) into it, so you're left with:

\(q=\dfrac{m}{M}*C*\Delta T \rightarrow C=\dfrac{q*M}{m*\Delta T}\)