Determine the prime factorization of 90. A. 2^2• 3 • 5 B. 2^3• 11 C. 2^2• 11 D. 2 • 3^2• 5 Would the answer be C?
2^2 is 4
so 2^2*11 = 4*11 = 44 which is NOT 90
what are the prime factors that multiply together to make 90?
90 = 2×3²×5
keep dividing it continuously by possible lowest no and then you'll get!
ok
Here's how you'd answer the question Start with 90 and divide by 2 to get 90/2 = 45. So 2 is a factor of 90 Then notice how 45/2 = 22.5 so 2 is NOT a factor of 45 ----------------- Now divide 45 by 3 to get 45/3 = 15. So 3 is a factor of 45 15 isn't a multiple of 2, but it's a multiple of 3. So 15/3 = 5 ------------------- We found the following prime numbers: 2, 3, 5 The '3' occurs twice, which is why the prime factorization is \(\Large 2*3^2*5\)
ohh ok
It might help to do a factorization tree like this |dw:1396124860887:dw|
@jim_thompson5910 explained what i was trying to say!! it's the correct and best method
circle the prime numbers in the factor tree |dw:1396124931335:dw|
when you multiply all those circled prime numbers out, you get the final answer
ohh ok, I didn't think of it that way, now i get it
ok, that's good things are clicking now
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