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Mathematics 8 Online
OpenStudy (anonymous):

draw ( in complex plane ) Re(z)=|z|

OpenStudy (♪chibiterasu):

That can't be graphed without any numerical values.

OpenStudy (anonymous):

it can be graphed :D

OpenStudy (♪chibiterasu):

Closest thing would be: \[\Re(z) \ge 0\] Which would look something like this: |dw:1396125228735:dw|

OpenStudy (♪chibiterasu):

Wow LaTeX. Re(z) >_ 0 :/

OpenStudy (anonymous):

u draw it in the real plane not complex :D

OpenStudy (anonymous):

oh , thx for the medal xD

OpenStudy (♪chibiterasu):

Np. :P

OpenStudy (anonymous):

it changed my colour :)

OpenStudy (♪chibiterasu):

Yeah you turn yellow at 50, Gold at 75, and green at 90. :3

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

i tried to solve it but not sure could u plz check my solution ? @jim_thompson5910 @ganeshie8 @ParthKohli @jdoe0001 @Nurali @zepdrix

jimthompson5910 (jim_thompson5910):

if all we care about is that Re(z) = |z|, then the imaginary part of z could be anything we want. So it could be positive or negative.

OpenStudy (anonymous):

Re(z)=|z| x = sqrt (x^2+y^2) x^2=x^2+y^2 y^2=0 |y|=0

jimthompson5910 (jim_thompson5910):

that's why the graph is essentially the right half-plane shaded.

OpenStudy (anonymous):

|dw:1396125689826:dw|

OpenStudy (anonymous):

only x-axis seems to be the region right ?

Parth (parthkohli):

a little imagination tells me that there's no imaginary part. why? the line joining the origin to the re-axis is equal in length as the line joining the complex number graphed.

OpenStudy (anonymous):

@jim_thompson5910 ? so what it could be ?

OpenStudy (anonymous):

so im i right ?

OpenStudy (anonymous):

What does the real part represent in the complex plane? what does |z| represent? You want all complex numbers such that the value of the real part is equal to the length of line formed by the complex number from the origin .

OpenStudy (anonymous):

|dw:1396126042633:dw| does this diagram help you in any way

OpenStudy (anonymous):

i already know that i just wanna check my answer a bove if u can see it :D

OpenStudy (anonymous):

any help ?

OpenStudy (anonymous):

@Mashy

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