Question

1. square root of 6 divided by square root of 27?

2.) 4 divided by square root of 5?

3.) square root of 5 divided by square root of 3?

4) square root of 3x squared y to the 3d power.

please help. i have so many questions. i dont understand math.

Answer 1

1. \[\frac{ \sqrt{6} }{ \sqrt{27} } = \sqrt{\frac{ 6 }{ 27 }}\]

Answer 2

The threes cancel, so we have \[\sqrt{\frac{ 2 }{ 9 }}\]
Then we convert it back to the original form,
\[\frac{ \sqrt{2} }{ \sqrt{9} }\]

sqrt 9 is 3, so our final answer is \[\frac{ \sqrt{2} }{ 3 }\]

Answer 3

2.

I believe that all you have to do here is rationalize the denominator, so we mulitply the top and the bottom by sqrt5/sqrt5. We can do this because it is equivalent to 1.

\[\frac{ 4 }{ \sqrt{5} } * \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{ 4\sqrt{5} }{ 5 }\]
and we are done.

Answer 4

3. This is the same as number 2, so we rationalize the denominator and multiply by sqrt3/sqrt3.
\[\frac{ \sqrt{5} }{ \sqrt{3} } * \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt{15} }{ {3} }\]
and we are done.

Answer 5

for number 4, could you restate the question in the equation form? I'm not quite sure what you are asking, did you mean \[\sqrt{3 x^2y}^ { 3}\]