Question

Can someone check this, please? Thanks in advance =)

Answer 1

\(\large \textit{area of a sector of a circle}=\cfrac{\theta \pi r^2}{360}\qquad
\begin{array}{llll}
\theta=\textit{angle in degrees}\\
r=radius
\end{array}\)

Answer 2

no is not 8

Answer 3

That's what I keep getting though

Answer 4

hm recall that radius is half the diameter

Answer 5

So the radius would be 8 right?

Answer 6

and that you're asked to find the SHADED area, no the NON-SHADED one

Answer 7

the shaded area will be anything BUT \(45^o\)

Answer 8

I'm confused.

Answer 9

Is 8 the area of the non-shaded area?

Answer 10

Would the area of the shaded sector be 56?

Answer 11

woops ... I was a bit caught up

yes is 56 \(\bf \textit{area of a sector of a circle}=\cfrac{\theta \pi r^2}{360}\implies \cfrac{(360^o-45^o) \pi \frac{diameter}{2}^2}{360}
\\ \quad \\
\cfrac{315 \pi 8^2}{360}\implies \cfrac{\cancel{20160} \pi}{\cancel{360}}\implies 56\pi\)

Answer 12

Thank you =)