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Mathematics 21 Online
OpenStudy (anonymous):

Graphing Equation questions.....can you help?

OpenStudy (anonymous):

I have 5 questions.

ganeshie8 (ganeshie8):

shoot

OpenStudy (anonymous):

Which is an equation is point-slope form of the line that passes through the points (4,5) and (-3, -1)? A. y+3=7/6(x+1) B. y+1=6/5(x+3) C. y+1=6/7(x+3) D. y-1=6/7(x-3)

ganeshie8 (ganeshie8):

start by finding the 'slope'

ganeshie8 (ganeshie8):

remember the slope formula ?

OpenStudy (anonymous):

Ok, I am not very well with finding slopes and stuff. Can you explain?

OpenStudy (anonymous):

Sorry...

ganeshie8 (ganeshie8):

slope between two points = (change in y)/(change in x)

ganeshie8 (ganeshie8):

(4, 5) and (-3, -1) x1 y1 x2 y2

ganeshie8 (ganeshie8):

change in y = y1-y2 = 5--1 = 6 change in x = x1-x2 = 4--3 = 7 so, slope = 6/7

OpenStudy (anonymous):

Ok.

ganeshie8 (ganeshie8):

next, use the point slope form of line : \(y - y_1 = m(x - x_1)\) \(m = slope = 6/7\)

ganeshie8 (ganeshie8):

plugin the second point : (-3, -1) x1 y1

ganeshie8 (ganeshie8):

plug them in the equation, wat do u get ?

OpenStudy (anonymous):

I'm so sorry I don't understand. By plug do you mean subtract them from each other? Like -3 subtract -1?

ganeshie8 (ganeshie8):

plug x1, y1 and m values in the equation of line

ganeshie8 (ganeshie8):

x1 = -3 y1 = -1 m = 6/7

ganeshie8 (ganeshie8):

\(\large y - y_1 = m(x-x_1) \) plug the values : \(\large y - -1 = 6/7(x--3) \) \(\large y +1 = 6/7(x+3) \)

OpenStudy (anonymous):

Ok. I see lol. This is very confusing, especially when you are just starting off with this stuff. Hopefully in the future I'll be better at this stuff. So the answer to the problem is option C: y+1=6/7(X+3) Thanks for explaining. I have four more left, are you willing to help me with those too?

OpenStudy (anonymous):

This one is with a graph.

OpenStudy (anonymous):

Which is an equation of the given line in standard form? A. –8x + 9y = 23 B. –8x + 9y = –23 C. –8x + 7y = 25 D. –9x + 8y = –23

OpenStudy (anonymous):

Oh and there goes you're medal!

ganeshie8 (ganeshie8):

look at the graph, do u see two points with their coordinates given on the line ?

ganeshie8 (ganeshie8):

below are the points on line : \(\large (-4, -1)\) \(\large (\frac{1}{2}, 3)\)

ganeshie8 (ganeshie8):

can u find 'slope' between them ? use the same method we have used before

ganeshie8 (ganeshie8):

slope = (change in y) / (change in x)

ganeshie8 (ganeshie8):

change in y = y2 - y1 = 3--1 = 4 change in x = x2 - x1 = 1/2--4 = 9/2 so slope = 4/9/2 = 8/9

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Ok I see now

ganeshie8 (ganeshie8):

next, use any one of the given points and write the equation in point-slope form

ganeshie8 (ganeshie8):

lets take the point (-4, -1) and slope = 8/9

ganeshie8 (ganeshie8):

see if u can write the equation of line ?

OpenStudy (anonymous):

Ok

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