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Using the given zero, find all other zeros of f(x) -2i is a zero of f(x) = x^4 - 32x^2 - 144 @agent0smith
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Recall that complex zeros always come in conjugate pairs. So if, \[\Large\sf x=-2\mathcal i\]is a zero, then so is,\[\Large\sf x=2\mathcal i\]Which means this polynomial has factors of,\[\Large\sf (x-2\mathcal i)(x+2\mathcal i)\]
Let's multiply out the brackets, after that we can do polynomial long division or synthetic division to simplify the polynomial.
So what do you get when you multiply out the two brackets? :o Understand how to do that?
You can also factor this since it's basically a quadratic equation\[\large x^4 - 32x^2 - 144 = (x^2 +4) (x^2 -36)\]then you can use diff. of two squares on the 2nd set of brackets
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