A&X Electrical makes a lamp. The Research department found that the life of the lamp is normally distributed with a mean of 5000 hours and a standard deviation of 450 hours. 6. BB Enterprises places a special order from A&X Electrical for 1000 lamps. If their contract states that A&X Electrical will replace all lamps that fail before 4000 hours. How many lamps should A&X Electrical expect to replace? is this calculated via central limit theorem?
i got a z value that was way too high doing the central limit theorem.
what is the z score for 4000 when the mean is 5000 and the std is 450 ?
-2.22
and what is the Pr(z < -2.22) ?
.0139
that means the chance of being -2.22 standard deviations below the mean (or in this problem, being a light bulb that lasts less than 4000 hours) is 0.0139 or about 13.9/1000 chance of failing. Round that to 14/1000 chance of failing.
The "expected # of failures" is the probability of failing times the number of bulbs
so 14 bulbs as .0139(1000) is 14 bulbs not including PARTIALS
or rounding up partial bulbs
It is just an estimate, but we know this much: the answer has to be a whole number because there are no "fractional" bulbs. The best we can do is either round to the nearest whole integer, or round up to the next biggest integer. so 14 sounds reasonable.
sounds good to meeeee!
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