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Mathematics 10 Online
OpenStudy (anonymous):

Find the domain of the given function. f(x) = square root x+8/(x+4)(x-6) @agent0smith

OpenStudy (anonymous):

Set the denominator equal to zero, solve, and exclusive those values from the domain. All other real numbers are permissible.

OpenStudy (agent0smith):

Domain of a rational function like this is found by finding where the denominator equals zero, since you can't divide by zero. \[\large (x+4)(x-6) \ne 0\]

OpenStudy (anonymous):

wait so what do i do

OpenStudy (anonymous):

is it x ≠ -8, x ≠ -4, x ≠ 6 @agent0smith

OpenStudy (agent0smith):

Plug in x=-8 to see why there's no problem with x being -8.

OpenStudy (anonymous):

all real numbers?

OpenStudy (agent0smith):

Reread the first two posts...

OpenStudy (anonymous):

x ≥ -8, x ≠ -4, x ≠ 6

OpenStudy (agent0smith):

Read the first two posts again :P

OpenStudy (anonymous):

x>0

OpenStudy (agent0smith):

Read what we said in the first two posts.

OpenStudy (anonymous):

i did

OpenStudy (agent0smith):

"Set the denominator equal to zero, solve, and exclude those values from the domain."

OpenStudy (anonymous):

are any of thoes answers right

OpenStudy (agent0smith):

You have too many answers.

OpenStudy (anonymous):

what do you mean

OpenStudy (agent0smith):

"is it x ≠ -8, x ≠ -4, x ≠ 6" "Plug in x=-8 to see why there's no problem with x being -8."

OpenStudy (anonymous):

and i did

OpenStudy (agent0smith):

Oh sorry i missed that there's a square root in this. \[\Large f(x) = \frac {\sqrt{x+8}} {(x+4)(x-6)}\]is this it?

OpenStudy (agent0smith):

If so, x ≥ -8, x ≠ -4, x ≠ 6 is right.

OpenStudy (anonymous):

I missed it too!

OpenStudy (anonymous):

yrs!

OpenStudy (agent0smith):

Good job then! :)

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