Find the domain of the given function. f(x) = square root x+8/(x+4)(x-6)
@agent0smith
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OpenStudy (anonymous):
Set the denominator equal to zero, solve, and exclusive those values from the domain. All other real numbers are permissible.
OpenStudy (agent0smith):
Domain of a rational function like this is found by finding where the denominator equals zero, since you can't divide by zero.
\[\large (x+4)(x-6) \ne 0\]
OpenStudy (anonymous):
wait so what do i do
OpenStudy (anonymous):
is it x ≠ -8, x ≠ -4, x ≠ 6
@agent0smith
OpenStudy (agent0smith):
Plug in x=-8 to see why there's no problem with x being -8.
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OpenStudy (anonymous):
all real numbers?
OpenStudy (agent0smith):
Reread the first two posts...
OpenStudy (anonymous):
x ≥ -8, x ≠ -4, x ≠ 6
OpenStudy (agent0smith):
Read the first two posts again :P
OpenStudy (anonymous):
x>0
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OpenStudy (agent0smith):
Read what we said in the first two posts.
OpenStudy (anonymous):
i did
OpenStudy (agent0smith):
"Set the denominator equal to zero, solve, and exclude those values from the domain."
OpenStudy (anonymous):
are any of thoes answers right
OpenStudy (agent0smith):
You have too many answers.
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OpenStudy (anonymous):
what do you mean
OpenStudy (agent0smith):
"is it x ≠ -8, x ≠ -4, x ≠ 6"
"Plug in x=-8 to see why there's no problem with x being -8."
OpenStudy (anonymous):
and i did
OpenStudy (agent0smith):
Oh sorry i missed that there's a square root in this.
\[\Large f(x) = \frac {\sqrt{x+8}} {(x+4)(x-6)}\]is this it?
OpenStudy (agent0smith):
If so, x ≥ -8, x ≠ -4, x ≠ 6 is right.
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