Find the inverse of the function. f(x)=^2+4/3
I assume it's f(x) = x^2 + 4/3
To the find the inverse, let's rewrite the equation, replacing f(x) with y. y = x^2 + 4/3
http://media.education2020.com/evresources/1103-02-06-00-00_v2_files/i0030000.jpg
Then, swap the places of x and y. So you'll get x = ... Then, solve for y again. Finally, replace y with f^(-1)(x), which means inverse of a function.
Oh, ok. f(x) = (x^2 + 4)/3 Same deal, can you follow my steps?
okay let me see
okay so you said swap the places of x and y..so 3/x^2+4?
i mean o x=3/x^2+4
Err, no try again. So we have this: \[y = \frac{x^2 + 4}{3}\]
This is what I mean by swap places: \[x = \frac{y^{2} + 4}{3}\]
ohh okay so umm whats next?
Solve for y. We need to get this in the correct form for the inverse notation.
i forgot how to solve.. do i just subtract 3 with 4 and y^2?
No. Let's get rid of the 3 in the denominator first. How can you do that?
i dont know :(
do i switch it again?
No, we're not switching it again. We're just solving for y. How about multiplying both sides by 3?
okay so i multiply 4*3 which is 12 and what about the y^2?
That is incorrect. Do you not know how to simplify fractions? \[x(3) = (\frac{y^2 + 4}{3})(3)\] \[3x = y^2 + 4\]
no i dont. i really suck at this. okay so you subtract 3 on each side or no?
i mean for the next step you did
I multiplied both sides by 3. It will cancel on the right side because 3/3 = 1. And x will just turn into 3x. Now, on the newest equation, how can we get y by itself?
Is there something you can subtract?
is it 4?
Yes, rewrite the equation now.
okay
wait do i subtract 4 on the 3x?
3x=y^2+4 -4 -4
like that?
Yes yes. What do you get now.
-1
i mean 1 lol
1=y^2
No, you can't subtract terms with different variables. 3x can only be added or subtracted by terms with x in them.
\[3x - 4 = y^2\] Do you know how to get rid of the power on the y now?
no
oh wait hold on
so is y^2 subtracted by 4 then? and 4 and 4 are crossed out
Yeah, on the right side. The 4's got cancelled out because we subtracted 4 from both sides.
Do you know about square roots?
yes
Good. Square root both sides so we can get rid of the squared term on the y.
square y^2? and 3?
im sorry but you could show me how you did it
nvm idk..
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