Question

for the function f(x) = ln x/x^2, find the approximate location of the critical point in the interval (0,5). (How to get the second x value) so far I have (1.6487,x)

Answer 1

take the derivative, set it equal to zero and solve for \(x\)
you got the derivative?

Answer 2

(1-2 log(x))/ (x^20

Answer 3

i assume you mean
\[\frac{1-2\ln(x)}{x^3}\]

Answer 4

set
\[1-2\ln(x)=0\] and solve for \(x\) to find your critical point

Answer 5

you good with that?

Answer 6

Hmm yes. I haven't solved yet, but for x I should have two values correct?

Answer 7

I got 1.648, but there are suppose to be two x's. How?

Answer 8

i get
\[\sqrt{e}\]

Answer 9

there are not two, not sure why there should be

Answer 10

Ohh I've found why, I must plug in the 1.648 into the original equation, so it reads ln(1.649)/1.649^2.