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Find an explicit solution of the given initial-value problem. sqrt(1-y^2)dx-sqrt(1-x^2)dy=0 when y(0)=1/2
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i got to the part of y=sin(arcsin(x)+C)
plugging y0=1/2
gives 1/2=Sin(C)
how do i get the constant out by its self?
is it correct if i jus do arcsin on both sides
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Assuming all your work is right so far, you can isolate C by taking the inverse sine of both sides. So what's \(\arcsin\dfrac{1}{2}\)?
pi/6
Right. And just to check: http://www.wolframalpha.com/input/?i=sqrt%281-y%5E2%29+dx-sqrt%281-x%5E2%29+dy%3D0%2C+y%280%29%3D1%2F2
so can i say my explicit solution is y=sin(arcsin(x)+(pi/6))
oh nice i totally forgot of wolframalpha today
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Yeah, that's it
thx
yw
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